Question

the sum of the digit of a two - digit number is 9.also nine times this number is twice the number obtained by reversing the order of the digit.find the number​

Answer 1

Answer:

18

Step-by-step explanation:

Let the ones digit be 'x'

'Therefore, tens digit=9-x

Original number=10(9-x)+x 90-10x+x=90-9x

On reversing the digits,

Ones digit=9-x

Tens digit=x

New number=10(x)+9-x

10x+9-x=9x+9 According to question,

9(90-9x)=2(9x+9)

or 9(90-9x)=2(9x+9)

or 810-81x=18x+18

or -81x-18x=18-810

or -99x= -792

or x=792/99

x=8

Ones digit=8

Tens digit=9-8=1

Original number=18

Thank u.