Question

The sum of the digit of a two digit number is 9 .Also,nine times this no.ia twice the no. Obtained by reversing the order of digit find the no.

Answer 1

Answer:

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Step-by-step explanation:

let the required two digit number be 10x+y

wherein digit at tens place is x and that of units place is y

so number obtained by reversing digits=10y+x

according to the first condition

x+y=9 (1)

according to the second condition

9(10x+y)=2(10y+x)

ie 90x+9y=20y+2x

so 11y=88x

ie y=8x (2)

substitute value of y in (1)

we get

9x=9

ie x=1

substitute value of x in any of two equations

we get y=8

so our required two digit number=10x+y

=(10×1)+8

=10+8

=18

hence our required two digit number is 18