the sum of the digit of a two digit number is 9 also nine times this number is it with the number obtained by reversing the order of the digits find the number
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Let tens digit no.be X and unit digit no.be Y
A/q
x+y=9
and 9 (10×x+y)=2 (10×y+x)
90x+9y=20y+2x
88x-11y=0
from 1st
11x+11y=99
88x-11y=0
......
99x=99
x=1
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