Question

. The sum of the digit of a two digit number is 9. Also the nine times this number is twice the number obtained by reversing the order of the digit. What is two equations when the unit digit is x and tens digit is y. *


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Answer 1

Answer:

the sum of digits f a two digit number is 9.also nine times this ... Let the unit digit and tens digits of the number be x and y ... Number after reversing the digits = 10x + y.

Step-by-step explanation:

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Answer 2

EXPLANATION.

Let the digit at ten's place be = x

Let the digit at unit place be = y

original number = 10x + y

reversing number = 10y + x

According to the question,

Case = 1.

The sum of digit of two digit number = 9

=> x + y = 9 ..... (1)

Case = 2.

Nine times the number is twice the number

obtained by reversing the order of the digit.

=> 9 ( 10x + y) = 2 ( 10y + x)

=> 90x + 9y = 20y + 2x

=> 88x = 11y

=> 8x = y ..... (2)

put the value of equation (2) in equation (1)

we get,

=> x + 8x = 9

=> 9x = 9

=> x = 1

put the value of x = 1 in equation (2)

we get,

=> 8(1) = y

=> y = 8

Therefore,

original number = 10x + y = 10 + 8 = 18