the sum of the digit of a two digit number is 9 if 45 is added to the number the digits are interchanged find the number
Answers
Answer:
Let xy be the two digit number.
x + y = 9
xy + 45 = yx
xy possibilities, i.e., sum of digits = 9 :
18, 27, 36, 45, 54, 63, 72, 81
xy + 45 should be a 2 digit number, thus xy should be lesser than ( 99 - 45 ).
Thus, xy < 54.
xy possibilities lesser than 54 = 18, 27, 36, 45
18 + 45 = 63
27 + 45 = 72
36 + 45 = 81
45 + 45 = 90
Therefore, xy is 27 ( as 27 + 45 = 72 , when the digits of 27 are interchanged, we get 72 ).
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Answer:
hi
Let xy be the two digit number.
x + y = 9
xy + 45 = yx
xy possibilities, i.e., sum of digits = 9 :
18, 27, 36, 45, 54, 63, 72, 81
xy + 45 should be a 2 digit number, thus xy should be lesser than ( 99 - 45 ).
Thus, xy < 54.
xy possibilities lesser than 54 = 18, 27, 36, 45
18 + 45 = 63
27 + 45 = 72
36 + 45 = 81
45 + 45 = 90
Therefore, xy is 27 ( as 27 + 45 = 72 , when the digits of 27 are interchanged, we get 72 ).
Step-by-step explanation:
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