the sum of the digit of a two digit number is 9. if 9 is added to the number the digits interchange their places .find the number
Answers
Answered by
67
let the unit place no. is y & ten place no. is x so the no. will be (10x+y)
given that x+y=9 .......(1)
acc. to the question -
10x+y + 9 = 10y+x
9(x-y) = -9
x-y = -1.......(2)
now by (1) & (2) we get
x=4 & y=5
So the required no is 45.
given that x+y=9 .......(1)
acc. to the question -
10x+y + 9 = 10y+x
9(x-y) = -9
x-y = -1.......(2)
now by (1) & (2) we get
x=4 & y=5
So the required no is 45.
Ayanhusain:
gow can the answer is 45 please tell me
actually right now i don't know about the ans. but ur ans. can be right plzz explain
How can you show me 9x-y=-9 please tell me
ok
10x+ y + 9 = 10y + x then taking the all terms of x & y one side of equal we get 10x-x+y-10y = -9
then 9x - 9y = -9
please tell me how can you find x=4and y=5
after adding eq (1) & (2) u can get that
and I'm sure about the answer actually it will be 45
Answered by
15
Answer: 45
Step-by-step explanation:
On adding 9 to the number, it's digits are reversed
Therefore Units digit is 9/9=1 more than the tens place.
Ten's digit is (9-1)/2=4.
Units digit =4+1=5.
The number is 45.
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