Question

the sum of the digit of a two digit number is 9. if the digits are reversed, the number is 63 more than the original. find the number​

Answer 1

Answer:

your answer is 3 and 6...

Step-by-step explanation:

pls follow me

Answer 2

Step-by-step explanation:

let the digit be =x

and tens digit be = y

so,

number is = 10y +× eq..5

Now A.T.Q ,

》》 x + y =9 eq..1

10 y + x = 9 eq..2

and 10x +y = 63 + 10 y +x eq...3

so from eq 2. we get .,

10 x + y = 63 + 10y +×

10x -× +y -10y =63

9× - 9y =63

9(×-y) =63

x - y = 7

x = 7+ y eq...4

now put eq .3 in eq 1

so ,

7 + y +y =9

.2y = 2

》》》 y = 1

and

x +1 =9

》》》 × = 8

so ,

the number is 》》 10y +× = 10(1) + (8)

= 10 +8 == [ 18 ]