the sum of the digit of a two digit number is 9. the number obtained by reversing the order of digit of the given number exceed the given number by 27.
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Let the two digit number be 10x + y
Given that the sum of the digits is 9
x + y = 9 (equation 1)
Given that the number obtained by interchanging the digits exceeds the given number by 27
10y + x = 10x + y + 27
9x - 9y = - 27
taking 9 as common
x - y = - 3 (equation 2)
Adding equation 1 and 2
x + y = 9
x - y = - 3
2x = 6
x = 3
3 + y = 9
y = 6
The number is 10x + y is 36
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