Question

the sum of the digit of a two digit number is 9 the number formed by reversing the digit is 45 more than the original number find the original number

Answer 1

let the number be xy.
$x + y = 9 \\ 10x + y + 45= 10y + x \\ 9x - 9y = - 45 \\ x - y = - 5$
subtract both equations
$2y = 14 \\ y = 7 \\ x + y = 9 \\ x + 7 = 9 \\ x = 2$
so the number is 27.

Answer 2

Answer:

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