Question

the sum of the digit of a two digits number is 9. Also, nine times this number is ​

Answer 1

Answer:

The sum of digits f a two digit number is 9. Also nine times this number is twice the number obtained by reversing the order of digit. Hence, the number is 10y + x = 10 × 1 + 8 = 18.

Answer 2

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Step-by-step explanation:

Given :-

The sum of digits f a two digit number is 9.

Also nine times this number is twice the number obtained by reversing the order of digit.

To Find :-

The Number

Solution :-

Let the unit digit and tens digits of the number be x and y

Number = 10y + x

Number after reversing the digits = 10x + y

According to the question,

⇒ x + y = 9 ... (i)

⇒ 9(10y + x) = 2(10x + y)

⇒ 88y - 11x = 0

⇒ -x + 8y =0 ... (ii)

Adding equation (i) and (ii), we get

⇒ 9y = 9

⇒ y = 1 ... (iii)

Putting the value in equation (i), we get

⇒ x = 8

Hence, the number is 10y + x = 10 × 1 + 8 = 18.

Step-by-step explanation:

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