The sum of the digit of a two number iss 15.if the number formed by reverseing difit is less than the original number by 27,find the original number and check your answer
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Answer:
Step-by-step explanation
Let the original number be 10y+x
And interchange number be 10x+y
From 1st condition
X + Y = 15...........1
From 2nd condition
10x+y-27=10y-x
10x-x+y-10y=27
9x-9y=27
Divide by 9
x-y=3..........2
Add equation 1 and 2
x+y=15
x-y= 3
2x=18
x= 18/2
x= 9.......
Put in equation 1
x+y = 15
9+y= 15
y= 15-9
y = 6
So, the original number is
10y+x
10×6+9
60+9
69
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