the sum of the digit of s 2digit no. is 7 .if digits are reversed ,the number formed 9less than the original no. find the
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Let the units digit be x.
The tens digit =7−x.
Original no. =10(7−x)+x=70−9x
If digits are reversed, no. =10x+7−x=9x+7
9x+7−2=2(70−9x)
9x+5=140−18x
27x=135
x=5
Tens digit =7−5=2
Number =25
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