Question

the sum of the digit of two- digit is 15. if the number formed by reversing the digit is less than the original number by 27, find the original number​

Answer 1

Let the 10 digit number be x

Let the one digit number be y

x+y=15

y=15-x (SUBSITUTION)

Original number:

10x+y

Reversed number:

10y+x

EQUATION:

 

10y+x=10x+y-27

Subsitute for y:

10(15-x)+x=10x+15-x-27

150-9x=9x-12

18x=162

x=9

y=15-9

y=6

Hence, the 10 digit number is 9 and the one digit number is 6, and the whole number is 96.

Answer 2

Hey mate, here is ur answer ♤♡◇♧

Given, The two digit number whose sul of digits = 15.....(i)

Let the digits be x , y

then the number will be = 10x + y

The number form by reversing it= 10y+x

Difference between these numbers= 10x+y-(10y+x)= 27

10x+y-10y-x=27

9x-9y=27

x-y=3

x= 3+y

Now, from eqn.(i)

where, x + y = 15

put 3+y in place of x

3+y+y=15

2y=12

y=6

x= 3+6=9

The original number is 96

Hope it helps.... plz mark as brainliest ☆