the sum of the digit of two digit number is 12 if the new number formed after reversing the digits it will greater than the original number by 54 find the original number
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Hi,
Here is your answer
Let the two digit number be 10x + y
Given that sum of the digits = 12
Therefore x + y = 12 (Equation 1)
Also given that if the number is reversed, the new number exceeds the original number by 54.
Therefore
10y + x = 10x + y = 54
9x - 9y = - 54
Taking 9 as common
x - y = - 6 (Equation 2)
Adding equation 1 and 2
x + y = 12
x - y = - 6
2x = 6
x = 3
3 + y = 12
y = 9
The original number is 10(3) + 9 = 39.
Hope this helps you.
Here is your answer
Let the two digit number be 10x + y
Given that sum of the digits = 12
Therefore x + y = 12 (Equation 1)
Also given that if the number is reversed, the new number exceeds the original number by 54.
Therefore
10y + x = 10x + y = 54
9x - 9y = - 54
Taking 9 as common
x - y = - 6 (Equation 2)
Adding equation 1 and 2
x + y = 12
x - y = - 6
2x = 6
x = 3
3 + y = 12
y = 9
The original number is 10(3) + 9 = 39.
Hope this helps you.
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0
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