the sum of the digit of two digit numbers is 12. if 18 is added to it the digit is reversed. find the number?
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The number 57.
Let the number be 10x+y; where x is at tens place and y at units place.
According to the question,
x+y = 12 → (1)
& 10x+y+18 = 10y+x
Therefore, 9x-9y = -18
Therefore, x-y = -2 → (2)
Adding (1)&(2) we get,
2x = 10
x = 5
Substituting, x=5 in (2) we get,
5-y = -2
Therefore, y = 5+2 = 7
Hence, the number is 10(5)+(7) = 50+7 i.e., 57
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