The sum of the digit of two number is 15. The number obtained by interchanging the digits exceed the given number by 9.find the number
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Let the number be xy.
Given,the sum of the digits of a two digit number is 15.
x+y = 15 ...(1)
Also, if the digits are interchanged the result exceeds the original number by 9.
10y+x=10x+y+9
10y+x-10x-y=9
9y-9x=9
y-x=1 ...(2)
(1)+(2) => 2y = 16
y = 16/2 = 8
(1) => x+8=15
x=15-8=7
Therefore the given number is 78 ...... (In first case x, was on the tens place soi had written 10x..and on second case after interchanging the digits means y gone to x place means now y is on tens place. Thats why i had written 10y)
Given,the sum of the digits of a two digit number is 15.
x+y = 15 ...(1)
Also, if the digits are interchanged the result exceeds the original number by 9.
10y+x=10x+y+9
10y+x-10x-y=9
9y-9x=9
y-x=1 ...(2)
(1)+(2) => 2y = 16
y = 16/2 = 8
(1) => x+8=15
x=15-8=7
Therefore the given number is 78 ...... (In first case x, was on the tens place soi had written 10x..and on second case after interchanging the digits means y gone to x place means now y is on tens place. Thats why i had written 10y)
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