The sum of the digit of two number is 9 if the number obtained by reversing the order of digit is 27 more than the original number find the original number
Answers
Answer:
The sum of the digits of the number 36 is 9. The number obtained by reversing the digits of 36 is 63. Thus, the number obtained by reversing the digits is greater than the original number by 27. Hence, we have verified our answer.
Answer:
Original number is 36
Step-by-step explanation:
Given that the sum of the digit of two number is 9 and the number obtained by reversing the order of digit is 27 more than the original number.
We need to find out the original number.
Let's say the ten's digit number is x and one's digit number is y.
- Original number = 10x + y
- Reversed number = 10y + x
As the sum of those numbers (x & y) is 9. So, we can write it like:
→ x+ y = 9
→ x = 9 - y ------ (eq 1)
As per second condition,
→ 10y + x - 27 = 10x + y
→ 10y - y + x - 10x = 27
→ 9y - 9x = 27
Take 9 as common,
→ y - x = 3
Substitute value of x in (eq 1)
→ y - (9 - y) = 3
→ 2y = 12
→ y = 6
Substitute value of y in (eq 1)
→ x = 9 - 6
→ x = 3
Original number = 10x + y = 10(3) + 6 = 36
Reversed number = 10y + x = 10(6) + 3 = 63
Therefore, the original number is 36.