Question

the sum of the digits in (1001)^3-1 is​

Answer 1

1001³ - 1

(100+1)³ - 1

using (a+b)³ = a³ + b³ + 3ab(a+b)

Here a = 100 and b = 1

=> 100³ + 1³ + 300(100+1) -1

=> 1000000 + 1 + 30000 + 300 -1

=> 1000000 + 30000 + 300

=> 1030300

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