Question

the sum of the digits in a 2 digit number is 10 . when we reverse the digits, then the difference of this number and the original number becomes 36 . Find the number​

Answer 1

Answer:

let the number be X+10Y

ATQ,

X+Y=10

X=10-Y. (1)

and

10X+Y-X-10Y=36

X-Y=4. (2)

on solving (1) and (2)

we get

X=6&Y=4

so the number will be

64