The sum of the digits in a three digit number is 15. If 99 is subtracted the digits will be in the reverse order. The digit in the tens place is equal to 2/3 times the sum of the digit in the hundreds place and units place. Find the number.
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Answer:-->it is wrong(Just look at eqn)
291
Step-by-step explanation:
x+y+z=15--Equation 1
100x+10y+z-99=100z+10y+x--equation 2
2/3 (y)=x+z---Equation 3
Substituting eq 3 in 1
5/3y=15
y=9--equation 4
Substituting eq 4 in eq 3,
6=x+z
6-x=z--equation 5
Substituting eq 5 and eq4 in eqn 2,
100x+90+(6-x)-99=600-100x+90+x
x=2-->Substituting this in eqn 3, z=1
Therefore, the number is 291
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