Question

The sum of the digits in a two digit number is 7 when the two digits are interchanged the value of the new number exceeds the value of the original number by forty five what is the original number

Answer 1

Answer:

Original num = 16

Step-by-step explanation:

Let the number be 10x + y

Sum of the digits = x + y = 7

Number when interchanged = 10y+x

(10y +x )-(10x +y) = 45

10y + x - 10x - y = 45

10y + (7-y) - 10(7-y) -y = 45

10y + 7 - y - 70 + 10y - y = 45

20y - 2y -63 = 45

18y = 45 +63 = 108

y = 108/18 = 12/2 = 6

x = 7-6 = 1

original number = 10×1 +6 = 16

Number on interchanging digit = 10×6+1 =61