The sum of the digits in the cube of 17 is
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2
Step-by-step explanation:
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To determine the digits at unit's place of the cubes of given numbers, first we need to find their cubes.
1
3
=1, 2
3
=8, 3
3
=27, 4
3
=64, 5
3
=125, 6
3
=216, 7
3
=343, 8
3
=512, 9
3
=729, 10
3
=1000
The digits at unit's place are 1,8,7,4,5,6,3,2,9,0
Let's arrange them in order, we get 0,1,2,3,4,5,6,7,8,9 as digits at unit's place.
Each digit occurs at the end of some cube. Hence one cannot conclude that some number is not a cube by looking at the last digit.
Answered by
6
Cube of 17 = 17 ³ = 4913
Sum of Digits of 4913 = 4 + 9 + 1 + 3
= 17
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