The sum of the digits of 2 -digit number is 12. if the number formed by reversing its digit is greater than the original number by 18. find the original number.
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Let ones digit =X
Tens digit = 12-X
Number fromed= 10(12-x)+x
Reverse number =10x+(12-x)
According to question
10(12-x)+x+18=10x+12-x
120-10x+x+18=10x+12-x
138-9x=9x+12
-9x-9x=12-138
-18x=-126
18x=126
X=126/8
X=63/4
By putting values u ll get answer
Hope this helps
Tens digit = 12-X
Number fromed= 10(12-x)+x
Reverse number =10x+(12-x)
According to question
10(12-x)+x+18=10x+12-x
120-10x+x+18=10x+12-x
138-9x=9x+12
-9x-9x=12-138
-18x=-126
18x=126
X=126/8
X=63/4
By putting values u ll get answer
Hope this helps
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