Question

the sum of the digits of 2 digit number is 7.if the digit are reversed in order, new number increased by 3 equals to 4 times the original number .find the original number.​

Answer 1

Answer:

Step-by-step explanation:

Let the two digit number be x and y

x+y=7

Answer 2

Answer:

Let ones place digit be x and tens place digit be y.

No.=10y+x

from case1:-

x +y=7

×=7-y------(i)

from case 2:-

10× +y +3=4 (10y+ ×)

10× + y+3=40y+ 4×

6×-39y=-3

2×-13y=-1-----(ii)

putting (i) in (ii)

14-2y-13y=-1

-15y=-15

y=1

from (i)

×=7-y

×=6

Number =10y+x

=16