the sum of the digits of 2digit no. is 9..if we interchange the no. We get 9 more than original no..
find the no. with step by step solution
Answers
Answer:
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Answer:
Let the digits of the original number be x and y
Hence, the original number is 10x + y (Assuming x to be the ten's digit and y to be the one's digit)
After interchanging the digits the new number will be 10y + x (After reversing, y becomes the ten's digit and x becomes the one's digit)
Condition 1: Sum of the digits is 9 ⇒ x + y = 9 --------- equation (i)
Condition 2: The number obtained by interchanging the digits is 27 greater than the earlier number.
⇒ New number = 27 + original number
⇒ 10y + x = 27 + (10x + y)
⇒ 10y + x = 27 + 10x + y
⇒ 10y - y + x - 10x = 27
⇒ 9y - 9x = 27
⇒ y - x = 3 -------- equation (ii)
By adding equation(i) and equation(ii):
x + y + y - x = 9 + 3
⇒ 2y = 12
⇒ y = 6
From equation(i): x + 6 = 9
⇒ x = 9 - 6 = 3
⇒ x = 3 and y = 6
⇒ The required number is 10x + y = 10 × 3 + 6 = 30 + 6 = 36
Hence the required number is 36
Step-by-step explanation:
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