The sum of the digits of 2digit number is 9. If the number formed by reversing it's digit is 27 less than the original number, find the original number
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let the number be 10 x + y
ATQ
x + y = 9
10y + x + 27
10 x + y
x - y = 3
solving of x and y
we get x = 6 and y = 3
therefore the number is 63
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