Question

the sum of the digits of a 2 digit no is 10 the digit in one place is nine time the digit at ten,s place find the no​

Answer 1

Answer:

use internett to get answer

Answer 2

Step-by-step explanation:

let digit at one's place is x

and digit at ten's place is x/9....

so x+x/9=10

9x+x/9=10

10x/9=10

10x=90

x=9

and x/9....or no.at ten's place is ....9/9=1....

so the no. is 19

1+9=10