The sum of the digits of a 2 digit no. is 6 on reversing its , the new no. Is 18 less than the original no. Find the no.
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let be the original no be 10x+y
and reversed no be 10y+x
so the sum of no
x+y=6
and second equation be 10x+y-18=10y+x
x-y=2 so by elimination x=4and y=2so answer is
42 or 24
and reversed no be 10y+x
so the sum of no
x+y=6
and second equation be 10x+y-18=10y+x
x-y=2 so by elimination x=4and y=2so answer is
42 or 24
su123198:
Thnx for your explaination
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