Question

the sum of the digits of a 2 digit no is 7. if the digits are reversed the new number increased by 3 equals four times the original number. find the number.​

Answer 1

Answer:

let the numbers be x,y

x+y=7................(1)

let the original number be 10x+y

let the second number 10y+x

according to the sum

10y+x=4(10x+y)-3

10y+x=40x+40y-3

39x-6y=-3

13x-2y=-1..........(2)

solving 1 and 2

x=1

y=6

so the original no is 10x+y=16.

Step-by-step explanation: