Question

The sum of the digits of a 2-digit no. is 8. The number obtained by interchanging the digits exceeds the given number by 18. Find the given numbers

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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• Let the ten's digit be 'x'.

• And, unit's digits be 'y'.
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• Then, it is given that x + y = 8....[equation i]
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• Then, the two digit number = 10x + y


• Now, the number obtained by interchanging its digit = 10y + x
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• Now, according to the question, new number exceeds old number by 18


=> 10x + y + 18 = 10y + x

=> 10x + y - 10y - x = -18

=> 10x - x - 10y + y = -18

=> 9x - 9y = -18

=> 9(x - y) = -18

=> x - y = -18/9

=> x - y = - 2.... [equation ii]
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• Now, adding equation i and ii,


x + y = 8

x - y = -2
(+) (+) (+)


=> 2x = 6

=> x = 6/2

=> x = 3

• Hence, x = 3
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• Now, substituting the value of x in equation i.


=> x + y = 8

=> 3 + y = 8

=> y = 8 - 3

=> y = 5

• Hence, y = 5
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• Therefore, the original number -

= 10x + y

= 10(3) + 5

= 30 + 5

= 35.


$<marquee>Hence, the digits are 3 and 5; and the number is 35.</marquee>$
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Thank you.. ;-)

Answer 2

Answer:

1. 35

Step-by-step explanation:

please add brainlist answer

Sameer raj