Question

The sum of the digits of a 2 digit number is 10. 36 is added to the number , the digits are reversed.Find the original number.​

Answer 1

Let the number be xy = 10*x + y

Given x + y = 10 (i)

and

10*x + y + 36 = 10*y + x (digits of original number reversed by adding 36)

9*x - 9*y = -36

x - y = -4 (ii) dividing throughout by 9.

Adding (i) and (ii):

x + y = 10

+(x - y = -4)

We get:

2*x = 6

or x= 3

Substituting for x in (i),

3 + y = 10

or y = 10 - 3 = 7

Therefore, the original number, xy (=10*x + y) = 30 + 7 = 37.

Check: 37 + 36 = 73.

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Answer 2

Answer:

37

Step-by-step explanation:

Let the the tens' digit be x.

Therefore, units' digit = (10-x). [Since, sum of the two digits= 10]

Therefore, B.T.P,

10x+10-x+36=10(10-x)+x

or, 9x+46=100-10x+x

or, 9x+46=100-9x

or, 18x=54

or, x=3

Therefore, the reqd. no. is 10x+10-x= 10*3+10-3=37

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