the sum of the digits of a 2 digit number is 10 if 36 is substracted from the number, its digits interchange their places. find the number
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x+y=10
y=10-x
(10x+y)-36=10y+x
10x+10-x-36=100-10x+x
9x-26=-9x+100
18x=126
x=7
∴y=10-7
=3
THE NUMBER IS 73
CHEERS!!!
y=10-x
(10x+y)-36=10y+x
10x+10-x-36=100-10x+x
9x-26=-9x+100
18x=126
x=7
∴y=10-7
=3
THE NUMBER IS 73
CHEERS!!!
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