The sum of the digits of a 2-digit number is 10. If we reverse the digits, the new number will be 54
more than the original number. What is the original number?
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let the unit digit =x
then tens digit=y
so number is 10y+x
x+y=10
if digits are reversed then no is,-
10x+y
now, 10x+y= 10y+x+54
9x-9y=54
divide by 9 on both sides
x-y= 6
x+y=10
from these two equations x=8, y=2
now the original no - 10×2+8 = 28
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