The sum of the digits of a 2-digit number is 10. If we reverse the digits, the new number will be 54 more than the original number. What is the original number?
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Answer: 28
Step-by-step explanation: see attachement.
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let x be in tenths place and y be in units place. The desired no is 10x+y, now if we reverse them we get10y+x....
According to question,
sum of the digits ,x+y=10.....
10y+x=54+10x+y.....
9y-9x=54
y-x=6
or,y=6+x.....
Now,x+y=10...
putting the value of y
x+6+x=10
2x=4
x=2
y=6+2=8
the no is 10x+y=10×2+8=28 is the no.
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