Question

.
The sum of the digits of a 2-digit number is 10. The digit in one's place is nine times the digit at
ten's place. Find the number,
​

Answer 1

Answer:

91

Step-by-step explanation:

let the digit at ten's place be x

digit at one's place be 9x

According to question,

9x+x=10

10x=10

x=1

therefore one's digit=9x=9

ten's digit=x=1

number=91