Question

The sum of the digits of a 2 digit number is 10. The number obtained by interchanging the digits exceeds
the original number by 36. Find the original number.​

Answer 1

Step-by-step explanation:

writing is not good so sorry

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Answer 2

Answer: 37

Let the -

• ten's digit be M

• one's digit be N

∴ Number = 10M + N

Sum of two digit number is 10.

=> M + N = 10

=> M = 10 - N ...(1)

(The number obtained by interchanging the digits exceeds the original number by 36.)

∴ Interchanged number = 10N + M

=> 10N + M = 10M + N +36

=> 10N - N + M - 10M = 36

=> 9N - 9M = 36

=> N - M = 4

=> N - (10 - N) = 4 [From (1)]

=> N - 10 + N = 4

=> 2N = 14

=> N = 7

Substitute value of N in (1)

=> M = 10 - 7

=> M = 3

•°• Original number = 10M + N

=> 10(3) + 7

=> 30 + 7

$\bold{37}$