Question

the sum of the digits of a 2-digit number is 11. The number obtained by adding 4 to this number is 41 less than the reversed number. Find the original number.

Answer 1

Let the number in the tens place be X and the number in the units place be Y

*[Calculations in the attaatchment]

From this we get the original number as 10X+Y
=83


HOPE IT HELPS

Answer 2

let two digits be x and y
then x+y=11........(1)

the number is 10x+y
the reversed number is  10y+x

therefore 10x+y+4=10y+x-41
9x-9y=45
x-y=-5

therefore , x=-5+y  .......(2)

By substitution method in (1) and (2)

-5+y+y=11
2y=16

y=8

x=-5+8
x=3

the number is 38