Question

The sum of the digits of a 2 digit number is 11. The number obtained by adding 4 to this number is 41 less then the reversed number. Find the original number

Answer 1

Answer:

38

Step-by-step explanation:

Let, two-digit number be 10x + y.

First case, x + y = 11.................(i)

Second case, 10x + y + 4 = 10y + x - 41

       or, 9x - 9y = - 45

      or, x - y = - 5.................(ii)

Solving (i) and (ii), we get

x = 3, y = 8

So, the required number is 38.