the sum of the digits of a 2 digit number is 11 when 27 is added to the number we get number with digit interchanged find the number
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Answered by
4
let x be the tens digit and y be units digit of two digit no
by given,
x+y=11
x=11-y .............(1)
by another condition,
10x+y+27=10y+x
9x+27=9y
by substituting from (1),.
9(11-y)+27=9y
99-9y+27=9y
y=126/18
question is wrong.we dont get whole number such no do not exists
by given,
x+y=11
x=11-y .............(1)
by another condition,
10x+y+27=10y+x
9x+27=9y
by substituting from (1),.
9(11-y)+27=9y
99-9y+27=9y
y=126/18
question is wrong.we dont get whole number such no do not exists
Answered by
5
Answer:
Step-by-step explanation:
Let tens digit number be x and ones digit number be y
So original number is 10x+y
According to question
x+y=11.
x=11-y. ------(1)
10x+y+27=10y+x. --------(2)
Using (1) in (2)
10(11-y)+y+27=10y+11-y
110-10y+y+27=9y-11
137-9y=9y-11
18y=126
y=7
x=11-7=4
So the number is 47
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