The sum of the digits of a 2-digit number is 12 and the difference of the digits is 4
Find the number if the tens digit is less than the ones digit
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Step-by-step explanation:
let the two digit no. is xy
thus it's sum will be 10x + y =12
difference Will be 10x - y =4
by solving it
+ 10x + y = +12
+ 10x - y = +4
we get x and y
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