The sum of the digits of a 2-digit number is 12. The number is 6 times the units digit. Find the number.
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Working this out algebraically:
Let the number by xy
The sum of the digits is 12:
x + y = 12 {equation 1}
The value of the number is 6 time the units digit:
6y = 10x + y
5y = 10x
y = 2x {equation 2}
Since x+y = 12 and y = 2x we have:
x + 2x = 12
3x = 12
x = 4
y = 2x = 2(4) = 8
xy = 48
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