Math, asked by bulbul5449, 3 days ago

the sum of the digits of a 2-digit number is 12. the number is 6 times unit digit. find the number.

Answers

Answered by assassinus6

Answer:

Step-by-step explanation:

Let the digits be x and y. Given x+y=12

The two digit number will be 10*x+y.

10*x+y=6*y

10x=5y

2x=y in x+y=12 gives x+2x=3x=12 which gives x=4

x=4 implies y=8 and the number is 10*4+8=48

Answered by Laxmipriyas007

Answer:

The number is 38

Step-by-step explanation:

Let the digit in the units place be equal to 'x'

Let the digit in the tens place be equal to 'y'

Then we get 2 digit number as 10y + x

Then the 2-digit number is =10y + x

Given that sum of the digits of a 2-digit number is 12

i.e., x + y = 12..................................( 1 )

The number is 6 times the unit digit.

Therefore,

10y + x = 6x,

10y = 5x,

2y = x .

Substitute x = 2y in equation ( 1 ),

2y + y = 12,

3y = 12,

y = 4

Putting the value of 'y' in x = 2y, we get

x = 2 x 4 = 8

Therefore, the number is 10y + x

= 30 + 8

= 38