Question

the sum of the digits of a 2-digit number is 12. the number is 6 times unit digit. find the number.​

Answer 1

Answer:

48

Step-by-step explanation:

Let the digits be x and y. Given x+y=12

The two digit number will be 10*x+y.

10*x+y=6*y

10x=5y

2x=y in x+y=12 gives x+2x=3x=12 which gives x=4

x=4 implies y=8 and the number is 10*4+8=48

Answer 2

Answer:

The number is 38

Step-by-step explanation:

Let the digit in the units place be equal to 'x'

Let the digit in the tens place be equal to 'y'

Then we get 2 digit number as 10y + x

Then the 2-digit number is =10y + x

Given that sum of the digits of a 2-digit number is 12

                        i.e., x + y = 12..................................( 1 )

The number is 6 times the unit digit.

Therefore,

                        10y + x = 6x,

                        10y = 5x,

                        2y = x .

Substitute x = 2y in equation ( 1 ),

                                      2y + y = 12,

                                      3y = 12,

                                       y = 4

Putting the  value of 'y' in x = 2y, we get

                         x = 2 x 4 = 8

Therefore, the number is 10y + x

                                        = 30 + 8

                                       = 38

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