the sum of the digits of a 2-digit number is 12. the number is 6 times the unit digit. Find th number.
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The number is 48.
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The sum of the digits of a 2-digit number is 12. The number is 48
Solution:
Let assume number at tens place = x
And number at units place = y
So number = 10x + y
Given that sum of two digits is 12
=> x + y = 12
=> y = 12 – x ------ (1)
Also given number is 6 times the unit digit
=> 10x + y = 6y
=> 10x – 5y = 0
=> 2x – y = 0 ------- (2)
Substituting value of x from equation (1) in equation (2) we get
=>2x –( 12 – x) = 0
=> 3x = 12
=>x = 4
From (2) y = 12 – x = 12 - 4 = 8
Hence required number is 10 x 4 + 8 = 48.
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