The sum of the digits of a 2-digit number is 15. The number obtained by reversing
the digits is 9 less than the original number. Find the number.
Answers
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Let the number at unit place = x
And the number at tens place = 15 - x
Number = 10×tens place + unit place
Original number = 10×(15-x)+x
=150 - 10x + x
=150 - 9x
Number formed on reversing the digit
= 10×x + 15 - x
= 10x + 15 - x
= 9x + 15
A.T.Q = 9x + 15 = 150 - 9x - 9
= 9x + 9x = 150 - 9 - 15
= 18x = 126
= x = 126/18
= 7
Unit digit = x = 7
Ten's digit = 15 - x
= 15 - 7
= 8
SO, original number = 87
And reversed number = 78
HOPE IT HELPS YOU
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THANK YOU
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