the sum of the digits of a 2-digit number is 16. if 12 is added to this number , the new number is 100. find the original number
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Answer:
Let
The number be 10x+y
Given That ,
= x + y = 16 ---- ( 1 )
And,
= 10x + y + 12 = 100
= 10x + y = 100 - 12
= 10x + y = 88 ----( 2 )
On subtracting equation 1 from equation 2 :
= 10x + y = 88
- ( x + y = 16 )
= 9x = 72
= x = 72/9
= x = 8
On putting x=8 in equation 1,
We get -
= 8 + y = 16
= y = 16 - 8
= y = 8
Therefore the number is
= 10 × 8 + 8 [ putting the value of x and y in 10x+y]
= 80+8
= 88
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