Question

the sum of the digits of a 2 digit number is 6.if the digits of the numbers are reversed the new number gets diminished by 18.find the original number
plss answer with full explanation

Answer 1

Answer:

Can you please learn how to use punctuation before posting on Quora again?

Let's set up a system with two variables: x = tens place of our answer, y = units place of our answer.

Digit sum of a two digit number is 6:

x+y=6

Reverse the digits and you get 18 less than the original value:

10y+x=10x+y-18

Now let's solve:

y=6-x

10(6-x)+x=10x+(6-x)-18

60-10x+x=10x+(6-x)-18

60-9x=9x-12

72=18x

x=4

y=6-4

y=2

So our original number was 42. Sum of digits is 6. Swap the order of the digits to make 24, and you have a number 18 less than the original number.

Answer 2

Answer:

The sum of the two digit number is 6 on reversing its digits the new number is 18 less than the original number find the number?

It's 42.

Let the tens digit be a, while the units digit will be b.

a+b=6⟹b=6−a

10b+a=10a+b−18

⟹9b=9a−18

⟹6−a=a−2

⟹2a=8

a=4⟹b=2

Thus the number is 42.

Verify:

4+2=6✓

42−18=24✓