Question

The sum of the digits of a 2-digit number is 6 . On reversing its digits the number is orignal number is 18 less than the original number . Find the number .
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Answer 1

Answer:

So our original number was 42. Sum of digits is 6. Swap the order of the digits to make 24, and you have a number 18 less than the original number. The sum of digits of a two-digit number is 13 and if subtracted 8 from the number both digits will be same in new number...

Answer 2

Answer: 42

Let the digit in tens place be x

Let the digit in ones place be y

So the number is "10x+y"

And the reversed number is "10y+x"

Given that

- x + y = 6...................... (i)

- 10y + x = 10x + y - 18

   x - 10x + 10y - y = -18

   -9x + 9y = -18

   x - y = 2.......................... (ii)

On solving the equations, we get

   x  +  y  =  6

+ x  -   y  =  2

=> 2x = 8

=>  x = 4

On substituting the value of x in equation (i), we get

=> x + y = 6

=> 4 + y = 6

=> y = 6 - 4

=> y = 2

Therefore the number is 10x + y = 42

Hope it's helpful....