Question

the sum of the digits of a 2-digit number is 6. on reversing its digits the new number formed is 18 less than the original number. find the orginal number. ​

Answer 1

Answer:

explanation:

Let's set up a system with two variables: x = tens place of our answer, y = units place of our answer.

Digit sum of a two digit number is 6:

x+y=6

Reverse the digits and you get 18 less than the original value:

10y+x=10x+y-18

Now let's solve:

y=6-x

10(6-x)+x=10x+(6-x)-18

60-10x+x=10x+(6-x)-18

60-9x=9x-12

72=18x

x=4

y=6-4

y=2

So our original number was 42. Sum of digits is 6. Swap the order of the digits to make 24, and you have a number 18 less than the original number.

Hope this help you

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