The sum of the digits of a 2-digit number is 7.If the numbers are reversed,the new number increase by 3 less then 4 times the original number.Find the original number.
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Answer:
16
Step-by-step explanation:
Let the unit place of original no. Be x and tenth place be tenth(7-x) or 10(7-x) or 70-10x
So the original no. will be 70-10x+x = 70-9x
After reversing let the unit place be (7-x) and tenth place be tenth(x) or 10x
So the reverse no. Will be 7-x+10x = 7+ 9x
So ATP,
{4(70-9x)}-3 = 7+9x
280 -36x -3 = 7+9x
277-36x = 7+9x
277-7 = 9x + 36x
270 = 45x
X= 270/45 = 6
So original no. Will be 70-9x = 70-9(6) = 70-54 = 16
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