Math, asked by armaankhurshidalam, 7 months ago

The sum of the digits of a 2-digit number is 7. The number formed by reversing the digit is 45 more than the original number. Find the original number. ​

Answers

Answered by harshkumardhruwe09
0

answer is 16

Step-by-step explanation:

▶ Given

i) The sum of the digits of a two digit number is 7

ii) The number formed by reversing the digit is 45 more than the original number

▶ Let :

i) Let the two digit number be 10x + y, where x and y are one's and ten's digits respectively

▶ According to the Question :

The sum of the digits of the number is 7

•°• x + y = 7 ....... ( i )

After reversing the digits, the number becomes 10y + x

The number formed by reversing the digit is 45 more than the original number

•°• 10y + x - ( 10x + y ) = 45

=> 10y + x - 10x - y = 45

=> 9y - 9x = 45

=> 9 ( y - x ) = 45

=> y - x = 5

=> x - y = - 5 ....... ( ii )

Adding eq ( i ) and ( ii ) , we get :

x + y = + 7

x - y = - 5

_____________________

2x = 2

x = 1

Substituting value of x in equation ( i ), we get :

x + y = 7

=> 1 + y = 7

=> y = 7 - 1

=> y = 6

•°• The number = 10x + y

= 10 × 1 + 6

= 10 + 6

= 16

✔✔ Hence, it is solved ✅✅

Similar questions